Hi guys, Just wondering for the quadratic formula do we make the roots a minus or plus??? For example: When using brackets for 4squared, that equals to 16. Without using brackets for 4squared, that equals to 16. In simpler terms, (4)squared=16 and 4squared=16. Thanks.

studyclix
Hi Zozosmithy,
If b = 4 then the b squared part would be (4) squared which would be 16. Hope this helps.

Zozosmithy
Ok and what if b= +4?? Thanks.

studyclix
if b=4 then b squared would be +16 also.
Any number squared will be a positive i.e. 3 squared = 9, (3) squared = 9

hamzamughees
if you have 4^2 (^ means to the power of) without brackets, the minus will not be squared, only the 4 will be squared and the minus sign will be added on to it later, e.g 4^2, the minus will be taken out, so 4^2 = 16, and then the minus will be added on, so 16. if you use the brackets, so (4)^2, the minus will also be squared,  *  = + (* means multiply) 4 * 4 = 16, so the answer of (4)^2 = +16, 4^2 = 16.
hope this helped:)

Dazzla16
Hi Zozosmithy! As you know this is the quadratic formula:
x=
b +/ sqrt(b^2  4ac)
________________
2a
when an equation is in the form: ax^2 + bx + c
You will notice the coefficient of b^2 is positive. That means, no matter what integer you sub in for b, b^2 will be positive.
Example: If b = 3, then b^2 = (3)^2 = 9.
In that case, you always have to put in the brackets.

Dazzla16
Hi Zozosmithy! As you know this is the quadratic formula:
x=
b +/ sqrt(b^2  4ac)
________________
2a
when an equation is in the form: ax^2 + bx + c = 0
You will notice the coefficient of b^2 is positive. That means, no matter what integer you sub in for b, b^2 will be positive.
Example: If b = 3, then b^2 = (3)^2 = 9.
In that case, you always have to put in the brackets.

Me
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