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    Pythagoras theorm and simultaneous equations brendan.harney.73

    How do you do the above!

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      To do pythagoras you must allow the square of the hypotenuse equal the sum of the squares of the other two sides of the triangle.

      EXAMPLE: you have a triangle with a hypotenuse labeled x and the two other sides are labeled 4 and 3

      so to find the value of x we say x to be squared = 4 to be squared + 3 to be squared

      this means x to be squared is =16+9

      x squared = 25

      to find x on its own you get the square root in this case its the square root of 25 which is 5.

      To do simultaneous equations you must make sure that either the x or y value are the same and have different signs(+ or -) if they do not you multiply one of the lines by a value that will let either the x or y value be equal and make sure the signs are different before you cross away the x or y value then solve for either either x or y and when you have, sub the value you have found back in to one of the original equations and solve for the other value you have not already found

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