Does anyone know how to find the nth term of sequences?
Halve the second difference to get the number of n2s for example if you the second difference of a sequence is +6 (which would be constant) you would divide 6 by 2 to get 3 therefore this becomes 3n2
In fact the following rules apply when determining the number of n2s
If the second difference is 2, you start with n2.
If the second difference is 4, you start with 2n2.
If the second difference is 6, you start with 3n2.
Write out the original sequence above the terms of your number of n2
Subtract the n2s from the sequence to give the Residue
The residue will either be constant or a linear sequence. If it is a linear sequence then work out its formula.
Finally add the number of n2s to the formula for the residue and this will be the formula for the original sequence.
The 2s are squared by the way (so like n2 = n squared). This only goes for quadratic sequences ^!
nice one these notes r good, not like toys r us