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    Solving quadratic equations Ciara.lynch

    Does anyone no how to solv quadratic equations

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      Marklogan

      use the -b formula

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      Ciara.lynch

      What's that

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      ajacob2013

      its on ur logtables i cnt type it in here

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      comet7852

      For the -b formula, let us say that your sum is 2x^2 ( two x squared ) + 3x - 4

      So 2^2 will be a

      3 will be b

      And -4 will be c

      We don't write down 3x because that will make the answer wrong

      So then your formula is -b±√b^2(b squared)-4ac ÷ 2a

      So then we substitute

      -3±√3^2-4(2)(-4)÷2(2)

      -3±√9+32÷4

      The ± means that it will be either + or -

      So -3+√9+32÷4= -1.4 (rounded)

      Or -3-√9+32÷4= -4.6 (rounded )

      So then

      x = 1.4

      Or

      x = 4.6

      Hope this helps ^°^

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      SryanBruen

      You use this formula only if it says in the question, round to two (or three) decimal places. When it does not say this, you factorise instead.

      X(squared) - 8x + 16 = 0

      First open up two brackets

      ( )( ) = 0

      Then add the x squared

      (X )(X ) = 0

      Then look at the sign in front of the last number (16 in this case). It's a + so, the signs in the brackets will be the same. Then you look at the middle number (8 in this case) and then look at the sign. Since the signs will be the same, you put down two minus' in the brackets. And then find factors of 16 and substitute two factors into the brackets that equal to minus 8.

      (X - 4) (X - 4) = 0

      -4X

      -4X

      = -8X

      ^ so this is the correct factors you have chosen

      Then you let each bracket equal 0

      X - 4 = 0

      X = 4

      X - 4 = 0

      X = 4

      Your answer is

      X = 4

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      Samtotty

      You can use the -b formula all the time if you like, some people aren't good at seeing factors so just always use it

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