The area of a circle is increasing at a rate of 6cm squared s 1.
i) Find in terms of r, dC
. 
. dr, the rate of change of the area with respect to the radius.
ii) Find, in terms of r, dA
. 
. dr, the rate of change of the area with respect to the radius.
iii) Hence, find dC
. 
. dA in terms of r.
iv) Find dC
. 
. dt, the rate of increase of the circumference, when the radius is 3cm.
If someone could tell me how to do this it would be greatly appreciated, thanks in advance :)

Zozosmithy
dC is over dr. dA is over dr. dC is over dA. dC is over dt.

Brian96
it looks like part i) and ii) are the same . Da/DR makes sense but Dc/Dr doesnt make any sense.

Me
Share files from your computer