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2021 Q6
Does anybody know how to do q6 part d ie The heat of combustion question, Im having major difficulty of doing it and I cant find any videos online of anyone attempting the question.
Leonator99
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Those calculations are very straightforward. Look at the number of carbon dioxide, water and sulfur dioxide there is. For example, there are 2 carbon dioxides and the figure they give you for carbon dioxide is -393.5 so simply multiply -393.5x2 to get -787. Do this for all three and then add 1867.5 to get your answer. Best of luck!
You have to multiply the figures by 2 as the heat of combustion is: the heat change when 1 mole of a substance is burned in excess oxygen. If there was only one mole of carbon dioxide in the equation then you don't need to multiply by anything you can just take the numbers as they are.
jojo6440
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go to www.theconcicalflask.ie they have good notes and videos where they do it
jojo6440
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**** www.theconicalflask.ie
conicalflask.ie goes through the equations really well in the thermochemistry/heats and fuels section of LC chemistry